PaulEngr wrote:
I'm surprised that you would ever see a DC voltage riding on the AC in a full wave rectifier, whether performed by free wheeling diodes or a valve (IGBT) arrangement. I have not actually see this in any of the equipment I work with.
However, if that is the case, from a shock hazard potential one of the big differences is that AC is almost always expressed in RMS terms whereas DC is absolute potential. I would make the attempt to read the shock hazard table using the worst case of both because there's not a great deal of difference at that voltage.
For arc flash, it's a much more difficult proposition. The major difference between DC and AC is that with AC, the actual arcing waveform is more or less a truncated, ringing square wave because the arc extinguishes at each zero crossing of the incoming power and then does not reignite until the voltage is high enough for this to occur. In the case you describe, we have no zero crossings so it would be inappropriate to add the DC and AC contributions separately. The AC component confounds the situation because the assumption that DC is...constant, does not apply. That being the case right now the DC equations are effectively just power x time x the energy flux through a sphere at a given working distance assuming 50% of the energy is released as radiant energy. I would model it using the DC equation from Annex D.8 using the RMS voltage which would be the DC equivalent with the AC component.
It is actually AC riding on DC (like a huge 480-volt, 60 Hz ripple), and it is really quite common for inverters depending on how the DC Bus is set up, I have seen inverters use a positive - negative bus arrangement (where the common connection between the two busses may actually grounded) and also use just a single DC bus. Inverters have come a long way, and we tend to think of them generating an AC voltage, when they are actually chopping up a DC voltage. I am not sure if that is significant in regards to arc flash or not.
You would see the AC riding on DC voltage on the inverter output to the motor. Inverters derive the output to the motor from a DC bus. The motor sees an alternating current. With a six-step inverter the voltage looks somewhat sinusoidal, but the current does not. With a PWM inverter, it is hard to see anything sinusoidal about the voltage, but the current that the motor sees is sinusoidal.
Inverter-duty motors require insulation rated for the bus voltage, which may be 650 - 720 volts. The effective voltage may be only 480 VAC, but the PWM waveform is peaking at bus voltage. If you try and use a standard motor on an inverter, it will only be a matter of time before the motor fails because the insulation is not rated for high enough voltage.
While the motor current crosses zero 60 times a second at base speed, and phase-to-phase on a scope, you will see zero volts, the actual voltage at the point where the motor crosses zero current might be 300 VDC phase to ground (The actual voltage to ground would vary depending on several factors).
Inverters have circuitry and logic to detect ground fault and phase-to-phase shorts as well. They often annunciate a fault without the accompanying loud noises and they generally will not produce an output when they detect a fault.