Artículos técnicos

Norma NFPA 70E

2017 NEC 240.87 Disparo instantáneo

The NEC requires that where a circuit breaker’s highest continuous current trip setting is rated or can be adjusted to 1200 Amps or higher, a method for reducing the arc energy must be provided. The 2014 Edition of the NEC provided a list of methods which included: zone-selective interlocking, differential relaying, energy-reducing maintenance switching and energy-reducing active mitigation systems or an approved equivalent means. The device’s instantaneous trip function was excluded from the list. The 2017 Edition of the NEC

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Bloqueo/Etiquetado: ¿Simple o complejo?

OSHA and NFPA 70E refer to a Simple LOTO as involving only one person/conductors/circuit part(s). A Complex LOTO is when there are conditions such as more than one person/circuit/shift/source involved – A complex LOTO has significantly more requirements. Here is this week’s question: Have you ever performed a complex LOTO? Yes No ANSWER   About Jim Phillips: Electrical Power and Arc Flash Training Programs – For over 30 years, Jim Phillips has been helping tens of thousands of people around the world,

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Marcación de límites AF

Hi, As per NFPA 70E, we have 3 boundaries to mark(AFB, limited and restricted). It is easy to mark and follow only one boundary which is greater than two. Sometimes AFB is more than limited approach boundary, so we marked the AFB and follow that. But sometimes AFB is very less for lighting boards and power distribution boards. Also it is not feasible to mark limited boundary as it is very big for small board placed in normal working area

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Relé de detección de arco eléctrico

What is the practice for the use of arc detection relay trip time in the arc incident energy calculations? NFPA-70E recognized arc detection relay but kept under “Other Methods” as opposed to “Incident Energy Reduction Method”. Does this means the arc flash relay tripping time should not be used for the arc incident energy calculations? READ MORE.

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Norma NFPA 70E

AS I understand it in NFPA 70 E 130.7 table any Panel 240 volts and below require Category 1 PPE. Also NFPA says any voltage 120 volts Phase to Phase is not required. If so shouldn’t Residential Electricians also comply? REPLY

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NFPA 70E y mantenimiento eléctrico mejorado

The duration of an arc flash can be greatly affected by the condition of electrical protective devices – i.e. circuit breakers, relays etc. NFPA 70E has been placing an increased emphasis on equipment being properly maintained. Has your company/client increased the emphasis on electrical maintenance as a result of 70E? Yes No Many clients – it depends CLICK to answer.

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Clasificaciones de la serie NEC 240.86

The National Electrical Code article 240.86 addresses series ratings with the following: Where a circuit breaker is used on a circuit having an available fault current higher than the marked interrupting rating by being connected on the load side of an acceptable overcurrent protective device having a higher rating, the circuit breaker shall meet the requirements specified in (A) or (B), and (C). (A) Selected Under Engineering Supervision in Existing Installations. The series rated combination devices shall be selected by

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Energía incidente no específica

Empecé a trabajar en una planta de fabricación donde la práctica anterior era poner <1,2 cal en sus etiquetas de arco eléctrico. La idea era que cualquier tramo de menos de varios cientos de pies alimentado desde un conducto de bus con fusibles LPS-RK1 sería inferior a 1,2 cal. Esto resulta ser cierto según mis cálculos. Incluso con las contribuciones máximas del motor, los cálculos se mantienen. ¿Alguien considera que esto cumple con la norma 70E? ¿Alguien más hace esto?

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Cálculos de cortocircuito y material de conductos

I recently came across a previous study that was completed for a facility that assumed a specific type of conduit [non-metallic/magnetic; PVC] vs what was actually installed [Rigid Meal Conduit], in digging into this deeper and looking at some of the short circuit calculations information available to me it appears that in the calculation they type of conduit [magnetic vs non-magnetic] can play a role in the amount of available fault current. When doing some quick simplistic calculations it appears

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